Consider an ideal gas confined in a cylinder with a frictionless piston. The reversible
expansion of gas takes place in a finite number of infinitesimally small
intermediate steps. If the Pext is infinitesimally less than internal
pressure of gas ‘P’ by ‘dP’. Then gas expands reversibly and piston moves
through a distance ‘dl’.
expansion of gas takes place in a finite number of infinitesimally small
pressure of gas ‘P’ by ‘dP’. Then gas expands reversibly and piston moves
through a distance ‘dl’.
Since dP is so small, for all practical purposes.
Pext. – Pgas = P.
One work done by gas in one infinitesimal step (dw) can be expressed as;
dw = P ´ dV. [ w = P ´ DV]
\dw = PdV.
If the gas expands from V1 to V2 during isothermal
reversible expansion. The total amount of work done would be equal to
reversible expansion. The total amount of work done would be equal to
What if the number of moles is not constant..?
ReplyDeletethere will apear an n in the last expression only which shows that the moles are n in number
Deletehow the number of mole will be not constant ,even then we put specific mole of gas in container then it remain constant.
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ReplyDeleteWhat if no of moles remains same
ReplyDeleteremove the n from the last expression so the resultant answer will be the answer to you question
Deletewhat will be the enthalpy change
ReplyDeleteFor a substance of fixed composition, the enthalpy changes with change in temperature at constant pressure, can be calculated as.....
DeleteDelta H= Integral Sign(a+bT+bT^-2) and Limits of integrals are T1 to T2
what will be the enthalpy change
ReplyDeleteFor a substance of fixed composition, the enthalpy changes with change in temperature at constant pressure, can be calculated as.....
DeleteDelta H= Integral Sign(a+bT+bT^-2) and Limits of integrals are T1 to T2
When will be work done +ve ?
ReplyDeleteW is +ve when the work is done ON the system by the surroundings.
DeleteWhen to use -nRT ln v2/v1 and -2.303nRTlogv2/v1
ReplyDeletehow then can we compare this with isothermal irreversible expansion work?
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ReplyDelete