For hydrogen atom, the energy of the revolving E, is the sum of its kinetic energy ( ½ mv

^{2}) and potential energy ( –e^{2}/r).E = ½ mv

^{2}– e^{2}/r ----------- (4)From equation (1)

mv

^{2}= e^{2}/rSubstituting the value of mv

^{2}in (3)E = ½ e

^{2}/r – e^{2}/rOr,

E = –e

^{2}/2r -------------(5)Substituting the value of ‘r’ from equation (3) in (5),

E = – e

^{2}/2 × 4π2me^{2}/n^{2}h^{2}**E = – 2 π**

^{2}me^{4}/n^{2}h^{2}By using proper integer for ‘n’ (quantum number), we can get the energy for each orbit.

thank you so much for this.....very helpful

ReplyDeleteMany many thanks. Can you pl give the derivation of schrodinger's equation and de Broglie's equation? It will be helpful for us.

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