Pages

Saturday, June 4, 2011

Deduction of Ideal Gas Equation

According to Kinetic Gas Equation
PV   = 1/3 mnu2
PV   =  2/3 * 1/2  mnu2
PV = 2/3 * 1/2   Mu2       
(where M = mn  &  M = total mass of gas)
PV = 2/3  × K. E                    (K. E  = 1/2  Mu2)
But   K. E  α  T      (one of the postulates of Kinetic Gas Equation)
K. E   =   K. T
PV    =  2/3 KT              
Where 2/3  is constant, K is also constant.
Thus, 2/3 K is also a constant and is found to be equal to ‘nR’
So,   2/3 K  =   nR             Where ‘R’ is called Gas Constant & ‘n’ is Number of Moles
PV   =   nRT

No comments:

Post a Comment